A ball is thrown at 15m/s at 60∘. What is its vertical velocity after 1s? (Take g\=10m/s2,sin60∘\=0.866)
Vertical velocity vy=v0sinθ0−gt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 m/s as the result, so option A is correct.
Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion Parameters and Calculations
