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#momentum conservation

6 public questions tagged with this topic.

A 5kg ball at 24m/s collides elastically with a stationary 15kg ball. What is the speed of the 5kg ball after collision?

For elastic collision, momentum and kinetic energy conserved: m1v1+m2v2=m1v1'+m2v2' and ½m1v1²+... per NCERT. Solving gives velocities matching 12 m/s. Inelastic loses energy. So option B is correct.

Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Work, Energy and Laws of Motion - Mixed Practice

A 9kg mass at 7m/s collides inelastically with a stationary 3kg mass. What is the final speed?

Momentum conservation: 9×7=(9+3)vf⇒63=12vf⇒vf=5.25m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Practice Set0

A 11kg mass at 6m/s collides inelastically with a stationary 4kg mass. What is the final speed?

Momentum conservation: 11×6=(11+4)vf⇒66=15vf⇒vf=4.4m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 4 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Practice Set0

A 7kg mass at 6m/s collides inelastically with a stationary 5kg mass. What is the final speed?

Momentum conservation: 7×6=(7+5)vf⇒42=12vf⇒vf=3.5m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 3 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Practice Set0

A 6kg mass at 4m/s collides inelastically with a stationary 2kg mass. What is the final speed?

Momentum conservation: 6×4=(6+2)vf⇒24=8vf⇒vf=3m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 3 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Practice Set0