A 3kg particle moves with velocity v\=−4j^m/s at r\=6i^m. What is the magnitude of its angular momentum about the origin
L = r×p = |i^j^k^6000−40| = k^(6×(−4)−0×0) = −24k^kg m2/s. Magnitude = 24kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 24 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
