A solid of 2 moles is heated from 300 K to 320 K . If its molar specific heat capacity is 25.5 J mol⁻¹ K⁻¹ , what is the
**Work and heat** both energy transfer modes, work organized, e.g., lifting weight, compressing gas, electrical current, heat random due to temperature difference, work can be completely converted to heat via friction, but heat cannot be completely converted to work (second law), energy transfer modes include work (mechanical, electrical) and heat (conduction, convection, radiation). Δ Q = μ C Δ T . μ = 2 , C = 25.5 , Δ T = 320 - 300 = 20 . Δ Q = 2 × 25.5 × 20 = 1020 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W
Ref: NCERT > Physics Book > Thermodynamics > Work Heat Distinction and Energy Transfer Modes
