How many grams of MgCO₃ are required to produce 4.4 g of CO₂ with excess HCl? (Molar masses: MgCO₃ = 84 g/mol, CO₂ = 44
Reaction: MgCO₃ + 2HCl → MgCl₂ + CO₂ + H₂O. Moles of CO₂ = 4.4/44 = 0.1 mol. 1 mol CO₂ from 1 mol MgCO₃; mass = 0.1 × 84 = 8.4 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple
