How many significant figures are present in the result of (0.0678 × 310.15)/0.0821?
0.0678 (3 sig figs), 310.15 (5 sig figs), 0.0821 (3 sig figs). Result ≈ 256.29; limited to 3 sig figs (256).
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Importance and Nature of Chemistry and Properties of Matter