A wire of length 2.2 m carrying 3.5 A is at 60° to a magnetic field of 0.2 T . What is the force on the wire?
Given: A wire of length 2.2 m carrying 3.5 A is at 60° to a magnetic field of 0.2 T . What is the force on the wire? Formula: Force F = I l B sin θ. Substitution & Calculation: F = 3.5 × 2.2 × 0.2 × sin 60° = 7.7 × 0.2 × 0.866 = 1.3336 approx 1.33 N . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.