A hydraulic lift uses a small piston of area 0.02m2 to exert a force of 200N to lift a load with a large piston of area
Pascal’s law: P = F1A1 = F2A2. F2 = F1×A2A1. F1 = 200N, A1 = 0.02m2, A2 = 0.1m2. F2 = 200×0.10.02 = 200×5 = 1000N. m = F2g = 100010 = 100kg.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.