#lithium deposition

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Li⁺ + e⁻ → Li . 1 mol Li (6.9 g) requires 1F. Moles = (2.07/6.9) = 0.3 mol , Charge = 0.3 × 96500 = 28950 C .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Li⁺ + e⁻ → Li . 1 mol Li (6.9 g) requires 1F. Moles = (2.07/6.9) = 0.3 mol , Charge = 0.3 × 96500 = 28950 C .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

View Details

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