9 public questions tagged with this topic.
The 4f orbitals have poor shielding due to their radial distribution, causing a greater effective nuclear charge and size reduction across the lanthanoids.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Given: The element with atomic number 71 belongs to which series? These values define the system as per NCERT data. Formula: Lutetium (Lu, Z=71) has [Xe] 4f^{14 5d¹ 6s², marking the end of the lanthanoid series (4f filling).. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Given: Which of the following lanthanoids exhibits the +2 oxidation state due to a half-filled 4f subshell? These values define the system as per NCERT data. Formula: Eu (Z = 63) forms Eu^{2+ with 4fâ·, a stable half-filled configuration.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Given: Which of the following lanthanoids exhibits a +4 oxidation state due to its noble gas configuration? These values define the system as per NCERT data. Formula: Cerium (Ce, Z = 58) forms Ce^{4+ with 4fâ° (noble gas-like), making it stable in this state.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Lanthanoid contraction leads to similar atomic sizes of Zr and Hf, but it does not affect ionization energy trends.
Ref: NCERT Class 12 Chemistry > Chapter 4: d and f Block Elements > Topic: Lanthanoids - Electronic Configuration and Lanthanoid Contraction
Gradual decrease in atomic/ionic radii of lanthanoids due to poor shielding by 4f electrons.
Ref: NCERT Class 12 Chemistry > Chapter 4: d and f Block Elements > Topic: Lanthanoids - Electronic Configuration and Lanthanoid Contraction
Lanthanoids primarily exhibit +3 oxidation state. Only a few elements like Eu and Yb show +2 oxidation state. Therefore, the statement that they primarily exhibit +2 oxidation state is incorrect.
Ref: NCERT Class 12 Chemistry > Chapter 4: d and f Block Elements > Topic: Lanthanoids - Electronic Configuration and Lanthanoid Contraction
Lanthanoids are not used as structural building materials due to their softness and high reactivity.
Ref: NCERT Class 12 Chemistry > Chapter 4: d and f Block Elements > Topic: Applications of d and f Block Elements
f-block elements have electrons filling f-orbitals (lanthanoids and actinoids). Ce (Z=58) is an f-block element, while Sc (d-block), Rb (s-block), and Xe (p-block) are not.
Ref: NCERT Class 11 Chemistry > Chapter 3: Classification of Elements and Periodicity in Properties > Topic: Modern Periodic Law and Present Form - Long Form Periodic Table
