For 2NO₂(g) N₂O₄(g) , if Kp = 4.0 at 350 K ( R = 0.0831 bar L/mol K ), what is Kc ?
Kp = Kc (RT)Δ n , Δ n = 1 - 2 = -1 , RT = 0.0831 × 350 ≈ 29.085 . Thus, Kc = Kp × RT = 4.0 × 29.085 ≈ 116.34 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
