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Δ Tb = i · Kb · m . Δ Tb = 1.87 × 0.52 × 0.1 ≈ 0.097 K .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Relative Lowering and Elevation of Boiling Point
Moles of fructose = (10/180) ≈ 0.0556 mol . Molality = (0.0556/0.4) ≈ 0.139 mol/kg . Δ Tb = 0.52 × 0.139 ≈ 0.0723 K .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Relative Lowering and Elevation of Boiling Point
α = 0.02 , [OH-] = 0.05 × 0.02 = 1.0 × 10⁻³ , pOH = 3 , pH = 14 - 3 = 11 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Ionic Equilibrium - Acids Bases and pH and Ionization of Weak Acids Bases
[OH-] = 0.1 × 0.00707 = 7.07 × 10⁻⁴ , pOH = 3.15 , pH = 14 - 3.15 = 10.85 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Acid-Base Theories - Arrhenius Bronsted-Lowry Lewis and Salts Hydrolysis
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