What is the product when (CH₃)2CHCl reacts with alcoholic KOH ?
Alcoholic KOH promotes elimination (E₂) in (CH₃)2CHCl , forming CH₂=CHCH₃ (propene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
