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#isochoric heating

3 public questions tagged with this topic.

Work Heat Distinction and Energy Transfer Modes

A gas at 10 atm and 80^circ C in a 8 L container is heated isochorically to 140^circ C . What is the final pressure?

**Modes of energy transfer** work is force times displacement, e.g., gas expansion W = P ΔV, heat is due to temperature gradient, internal energy change same for different combinations of Q and W, e.g., same ΔU can be achieved by adding heat at constant volume or doing work adiabatically, illustrating equivalence but distinction in mechanism. For isochoric: (P₁)/(T₁) = (P₂)/(T₂) . P₁ = 10 atm , T₁ = 80 + 273 = 353 K , T₂ = 140 + 273 = 413 K . (10)/(353) = (P₂)/(413) ⇒ P₂ = (10 × 413)/(353) ≈ 11.7 atm . Using first law ΔU = Q - W,

Ref: NCERT > Physics Book > Thermodynamics > Work Heat Distinction and Energy Transfer Modes

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Specific Heat Capacity and Latent Heat

An ideal gas absorbs 1000 J of heat in an isochoric process, increasing its temperature by 20 K . What is the number of

**Heat capacity** at constant pressure C_p and volume C_v, C_p = C_v + R per mole, for solids Dulong-Petit C_v≈3R≈25 J/mol·K. Specific heat and latent heat govern temperature changes and phase transitions, Q = m c ΔT for heating, Q = m L for melting/boiling at constant T. For isochoric process: Δ Q = μ C_v Δ T . Δ Q = 1000 , C_v = 20 , Δ T = 20 . 1000 = μ × 20 × 20 ⇒ μ = (1000)/(400) = 2.5 moles . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P

Ref: NCERT > Physics Book > Thermodynamics > Specific Heat Capacity and Latent Heat

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