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#inorganic chemistry

181 public questions tagged with this topic.

What is the number of unpaired electrons in [Cr(Hâ‚‚O)6]^{3+ ?

Given: What is the number of unpaired electrons in [Cr(H₂O)6]^{3+ ? These values define the system as per NCERT data. Formula: Cr³⁺ ( d³ ) with H₂O in an octahedral field has 3 unpaired electrons ( t_{2g³ ), as it’s a d³ system.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

How many optical isomers are possible for [Cr(Câ‚‚Oâ‚„)3]^{3- ?

[Cr(Câ‚‚Oâ‚„)3]^{3- is octahedral with three bidentate oxalate ligands, lacking symmetry, and forms two optical isomers (d and l enantiomers). This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

What is the magnetic moment (in BM) of [Ni(NH₃)6]^{2+ ?

Given: What is the magnetic moment (in BM) of [Ni(NH₃)6]^{2+ ? These values define the system as per NCERT data. Formula: Magnetic moment = sqrt2(2+2) = sqrt8 approx 2.83 BM.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Ni²⁺ ( d⁸ ) with NH₃ (moderate field) in an octahedral field is high spin ( t_{2g⁶ e_g² ), with 2 unpaired electrons. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

The number of moles of I^- oxidized by 1 mole of KMnOâ‚„ in acidic medium to form Iâ‚‚ is:

Given: The number of moles of I^- oxidized by 1 mole of KMnO₄ in acidic medium to form I₂ is: These values define the system as per NCERT data. Formula: 1 mole KMnO₄ oxidizes 5 moles I^- (10/2 = 5).. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: 2MnO₄^- + 16H^+ + 10I^- -> 2Mn^{2+ + 8H₂O + 5I₂ . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

What is the number of unpaired electrons in [Mn(Hâ‚‚O)6]^{2+ ?

Given: What is the number of unpaired electrons in [Mn(H₂O)6]^{2+ ? These values define the system as per NCERT data. Formula: Mn²⁺ ( d⁵ ) with weak field H₂O in an octahedral field is high spin ( t_{2g³ e_g² ), with 5 unpaired electrons.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

The number of unpaired electrons in Ti^{3+ (Z = 22) is:

Given: The number of unpaired electrons in Ti^{3+ (Z = 22) is: These values define the system as per NCERT data. Formula: Ti: 3d² 4s². This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Ti^{3+ : 3d¹ (loses 2 from 4s, 1 from 3d). 1 unpaired electron. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

What is the primary valence of nickel in NiCl₂ · 6H₂O ?

In NiCl₂ · 6H₂O, formulated as [Ni(H₂O)6]Cl₂, the primary valence is the oxidation state of Ni, satisfied by 2 ionizable Cl^- ions, so it is 2. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

What is the formula of tetraamminediaquacobalt(III) chloride?

Co³⁺ with 4 NH₃ and 2 H₂O (neutral) forms [Co(NH₃)4(H₂O)2]^{3+, balanced by 3 Cl^-, giving [Co(NH₃)4(H₂O)2]Cl₃ . This follows from NCERT principle where relation explains outcome clearly for students.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

Which complex has the highest number of unpaired electrons?

[Fe(H₂O)6]^{3+ (Fe³⁺, d⁵ ) with weak field H₂O is high spin ( t_{2g³ e_g² ), with 5 unpaired electrons, the highest among the options. This follows from NCERT principle where relation explains outcome clearly for students.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

What is the formula for hexaamminecobalt(III) sulphate?

Co³⁺ with 6 NH₃ forms [Co(NH₃)6]^{3+ . Sulphate ( SO₄^{2- ) requires 3 units to balance two +3 complexes, giving [Co(NH₃)6]2(SO₄)3 . This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

The oxidation state of cobalt in CoCl₂ is:

In CoCl₂, Cl = -1 (2 chlorines = -2). For neutrality, Co = +2. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

The oxidation state of sulfur in SO_3 is:

Given: The oxidation state of sulfur in SO_3 is: These values define the system as per NCERT data. Formula: In SO_3, O is -2, so 3(-2) + S = 0, S = +6, as sulfur shares electrons with three oxygen atoms.. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.