How much ice at 0∘C will melt if 16744J of heat is supplied? (Latent heat of fusion of ice = 3.35×105J kg−1)
Given: Q = 16744J, Lf = 3.35×105J kg−1. Q = mLf⇒m = QLf = 167443.35×105≈0.05kg = 50g. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 50 g. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Chapter 11: Thermal Properties – Calorimetry.