Calculate Δ S for the fusion of 36 g of ice at 273 K if Δ Hfus = 6.01 kJ/mol. (Molar mass of H₂O = 18 g/mol)
Moles = 36 / 18 = 2 mol, Δ S = n × Δ Hfus / T = 2 × 6.01 × 10³ / 273 = 44 J/K.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Gibbs Energy and Gibbs Energy Change and Equilibrium