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#HNO₃

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A solution of HNO₃ has a molarity of 0.8 M and a density of 1.03 g/mL. What is its molality? (Molar mass: HNO₃ = 63 g/mo

Mass of 1 L solution = 1000 × 1.03 = 1030 g. Mass of HNO₃ = 0.8 × 63 = 50.4 g. Mass of water = 1030 − 50.4 = 979.6 g = 0.9796 kg. Molality = 0.8 / 0.9796 ≈ 0.816 m.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Concentration Terms - Molarity Molality and Mole Fraction