3 public questions tagged with this topic.
Henry’s law: p = KH · x . x = (4/80) = 0.05 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
Initial: 10 = KH · 0.05 , KH = 200 bar . New solubility = 0.1 mol/kg at same pressure. 10 = KH' · 0.1 , KH' = 100 bar .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
Initial: p = 250 · x . New: 10 = KH' · 2x . Assume initial p = 5 bar , then x = (5/250) = 0.02 . New x = 0.04 , 10 = KH' × 0.04 , KH' = 250 bar . Recalculate: KH' = (10/0.04) = 250 bar (consistent).
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Relative Lowering and Elevation of Boiling Point
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