Water flows at 3.5m/s at 4.5m height with pressure 1.5×105Pa. What is the pressure at 2.5m height with speed 4.5m/s? (ρ\
Bernoulli’s: P1+12ρv12+ρgh1 = P2+12ρv22+ρgh2. Left: 1.5×105+12×1000×12.25+1000×9.8×4.5 = 1.5×105+6125+44100 = 2.00225×105. Right: P2+12×1000×20.25+1000×9.8×2.5 = P2+10125+24500 = P2+34625. 2.00225×105 = P2+34625, P2 = 1.656×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.65 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.