Water flows at 2.0m/s at 1.5m height with pressure 1.65×105Pa. What is the pressure at 0.2m height with speed 3.0m/s? (ρ
Bernoulli’s: P1+12ρv12+ρgh1 = P2+12ρv22+ρgh2. Left: 1.65×105+12×1000×4+1000×9.8×1.5 = 1.65×105+2000+14700 = 1.817×105. Right: P2+12×1000×9+1000×9.8×0.2 = P2+4500+1960 = P2+6460. 1.817×105 = P2+6460, P2 = 1.7524×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.75 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.