We use cookies to improve your experience and understand how Examtube is used. You can accept analytics cookies or continue with essential cookies only.
Privacy policy5 public questions tagged with this topic.
Elimination (E₂) of CH₃CH₂CHBrCH₂CH₂CH₃ with alcoholic KOH forms CH₃CH₂CH=CHCH₂CH₃ (3-hexene) per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
CH₃CH₂CH₂CH₂CH₂I reacts with excess NH₃ via SN₂ to form CH₃CH₂CH₂CH₂CH₂NH₂ (pentylamine) after heating.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
This is a Wurtz reaction, coupling two CH₃CH₂CH₂CH₂I molecules to form CH₃CH₂CH₂CH₂CH₂CH₂CH₂CH₃ (octane).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Alcoholic KOH promotes elimination (E₂) in (CH₃)2CHCH₂Br , forming (CH₃)2C=CH₂ (2-methylpropene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Alcoholic KOH promotes elimination (E₂) in CH₃CH₂CH₂CHBrCH₃ , forming CH₃CH₂CH=CHCH₃ (2-pentene) per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
This page is supported by advertisements. An ad blocker is stopping those ads from loading, so we cannot show the rest of the page yet. Pause the blocker for this site, then continue. We will check again automatically.
You can keep using this site after advertisements are allowed to load.
