6 public questions tagged with this topic.
A benzylic halide has the halogen on a carbon directly attached to a benzene ring. C₆H₅CH(CH₃)Cl (1-chloroethylbenzene) is benzylic.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
CH₃CH₂CH₂Br undergoes SN₂ substitution with NaSCH₃ to form CH₃CH₂CH₂SCH₃ (methyl propyl sulfide).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
Elimination (E₂) with alcoholic KOH favors tertiary halides due to stable alkene formation. (CH₃)3CBr reacts fastest.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
A vinylic halide has the halogen on a carbon of a C=C bond. CH₃CH=CHBr (1-bromopropene) is vinylic.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nucleophilic Substitution Reactions - SN1 and SN2 Mechanisms
SN₁ reactivity increases with carbocation stability. (CH₃)3CCl (tertiary) forms a stable tertiary carbocation, making it most reactive.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nucleophilic Substitution Reactions - SN1 and SN2 Mechanisms
C₆H₅CH₂Cl (benzyl chloride) forms a stable benzylic carbocation via SN₁ , reacting instantly with AgNO₃ to form AgCl .
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nucleophilic Substitution Reactions - SN1 and SN2 Mechanisms
