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#focal point

5 public questions tagged with this topic.

What ensures that a convex lens can focus light from a plane wave into a single point?

**Huygens principle** predicts shape of wavefront after propagation, for point source close spherical, far plane, after reflection from plane mirror spherical wave becomes spherical with centre mirrored, plane wave remains plane but direction changes angle of incidence equals reflection, after passing through thin prism plane wavefront tilts due to different path. The lens delays the central part of the plane wave more than the edges due to its thickness, transforming it into a spherical wavefront converging at the focus. Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I = I₀ cos²θ, n = c/v, sinC

Ref: NCERT > Physics Book > Wave Optics > Wavefront and Huygens Principle

Why does a concave mirror form a real image when the object is placed beyond the focal point?

**Two lenses in contact** behave as single lens with power sum, magnification product m = m₁×m₂. For f₁=20 cm (P₁=5 D), f₂=-20 cm (P₂=-5 D) in contact, P=0, F infinite, afocal system, beam emerges parallel, principle of corrective lenses for myopia/hypermetropia. When the object is beyond the focal point of a concave mirror, the reflected rays converge to a point on the same side as the object. This convergence of actual rays results in a real image that can be projected onto a screen, typically inverted relative to the object. Substituting values gives Due to rays converging to a point after

Ref: NCERT > Physics Book > Ray Optics > Combination of Lenses and Lens Systems

In a convex lens, if an object is placed at the focal point, where is the image formed?

**Refraction at spherical surface** formula n₁/u + n₂/v = (n₂-n₁)/R governs single surface, extension to two surfaces yields lens maker. Double convex with equal |R| has f = R/[2(n-1)], for R=12 cm, n=1.5, f=12 cm, illustrating dependence on curvature and index. For a convex lens, when the object is at the focal point (F), the rays after refraction become parallel and do not converge to a point on the other side. The image is formed at infinity, as the rays appear to diverge from an infinitely distant point when traced backward. Substituting values gives At infinity, which matches expected ima

Ref: NCERT > Physics Book > Ray Optics > Refraction at Spherical Surfaces and Lens Maker's Formula

In a concave mirror, what prevents the formation of an image when the object is placed at the focal point?

**Refractive index** n = c/v, water 1.33 means light 1.33 times slower than vacuum. Passing from water to air at 49°, n₁ sinθ₁ =1.33×sin49°≈1.33×0.755=1.004>1, so sinθ₂>1 impossible, total internal reflection occurs, no refraction. When the object is at the focal point of a concave mirror, the reflected rays become parallel and do not converge to a point. This results in the image being formed at infinity, meaning no distinct image forms at a finite distance. Substituting values gives Parallel reflected rays forming image at infinity, which matches expected image position and magnification fro

Ref: NCERT > Physics Book > Ray Optics > Refraction at Plane Surfaces and Snell's Law

Why does the image formed by a convex lens become real and inverted when the object is moved beyond the focal point?

**Concave mirror image formation** depends on object position: beyond C real inverted diminished between F and C, at C real inverted same size at C, between C and F real inverted magnified beyond C, at F image at infinity, within F virtual erect magnified behind mirror. Beyond the focal point, a convex lens converges light rays to a point on the opposite side of the lens. This convergence forms a real image, and because the rays cross over, the image is inverted relative to the object’s orientation. Substituting values gives Due to convergence of rays on the opposite side, which matches expect

Ref: NCERT > Physics Book > Ray Optics > Reflection by Spherical Mirrors and Mirror Formula