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The equation of continuity (Av = constant) for an incompressible fluid in steady flow implies that as the cross-sectional area decreases, the velocity must increase to maintain a constant mass flow rate.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Continuity equation: A1v1 = A2v2. A1 = 0.07m2, v1 = 2.4m/s, A2 = 0.035m2. v2 = A1v1A2 = 0.07×2.40.035 = 4.8m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.8 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
In viscous flow, the no-slip condition states that the fluid layer in contact with a stationary surface adheres to it due to frictional forces, resulting in zero velocity relative to the surface.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
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