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#F2 generation

14 public questions tagged with this topic.

Biochemistry and Aptitude and Reasoning

In the incomplete dominance of a monohybrid, the number of phenotypes in the F2 will be

The principle of quantitative reasoning explains that ratio, percentage and series logic determine correct calculation. Hence 3 fits best because it meets mathematical and logical criteria, as documented in authoritative sources on aptitude and reasoning.

Ref: Agrawal, Quantitative Aptitude for Competitive Examinations, Chapter 5, Logical Reasoning and Probability, covers ratios, percentages, series completion, time-distance and analytical reasoning explaining problem-solving strategies for competitive assessments.

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Aptitude and Reasoning

The number of phenotypes in the F2 of the dihybrid will be

This outcome reflects quantitative reasoning, where ratio, percentage and series logic determine correct calculation. Option C captures this correctly because it meets mathematical and logical criteria, consistent with textbook descriptions and experimental observations in aptitude and reasoning.

Ref: Agrawal, Quantitative Aptitude for Competitive Examinations, Chapter 5, Logical Reasoning and Probability, covers ratios, percentages, series completion, time-distance and analytical reasoning explaining problem-solving strategies for competitive assessments.

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Linkage and Mapping

In Morgan’s experiment, parental phenotypes in F2 were about

Morgan's experiment crossed heterozygous F1 females carrying coupling configuration of recessive black body b and vestigial vg alleles to homozygous recessive tester males for phenotypic scoring. Unlinked expectation predicts fifty percent parental and fifty percent recombinant phenotypes yet observed parental classes dominated around ninety-eight point seven percent while recombinants rare around one point three percent indicating tight linkage preventing separation. Excess of parental types demonstrated genes reside on same chromosome with infrequent crossover events foundational evidence fo

Ref: Griffiths et al., Introduction to Genetic Analysis, 12th ed., Chapter 5: Morgan's Parental Excess 98.7% Demonstration

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Genetic Crosses

A dihybrid cross AaBb × AaBb produces how many phenotypic classes in F2?

A dihybrid individual AaBb with unlinked genes can form four gamete types AB, Ab, aB, ab through independent assortment during meiosis. Selfing AaBb x AaBb produces 4x4=16 genotypic combinations collapsed by complete dominance at each locus. Phenotypically, genotype classes group into A-B- displaying both dominant traits, A-bb showing first dominant alone, aaB- second dominant alone, aabb both recessive. Thus four distinct phenotypic classes appear despite nine genotypic classes. Distinction highlights phenotype versus genotype numbers and forms basis for modified ratios when epistasis operate

Ref: Pierce, Genetics: A Conceptual Approach, 7th ed., Chapter 3: Phenotypic Classes in Dihybrid F2

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