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#disk

3 public questions tagged with this topic.

Vector Product and Rotational Kinematics

A uniform disk of mass 2kg and radius 0.2m rotates about its center with an angular speed of 10rad/s. What is its rotati

Rotational KE: K = 12Iω2. Moment of inertia of a disk: I = 12MR2 = 12×2×(0.2)2 = 0.04kg m2. K = 12×0.04×(10)2 = 0.02×100 = 2J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Rotational Motion Applications

A uniform circular disk of radius 3m and mass 12kg has its center at (0,0). What is the position of its center of mass?

For a uniform circular disk, the center of mass is at its geometric center. Given center at (0,0), CM position = (0,0). As per NCERT, applying relevant law/formula with correct units and sign convention leads to (0,0). This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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