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The logic is straightforward: we verify 1 14, 2 14, 3 14 by full calculation: use standard identity, substitute, simplify step by step to reach 1 14, 2 14, 3 14.
Ref: NCERT Mathematics Class XII — Vectors and 3D Geometry
Let's break it down: after simplifying, ± 3 is left. The method is simple: formula → substitution → calculation → answer.
Ref: NCERT Mathematics Class XII — Vectors and 3D Geometry
Notice that we verify ± 1/ 3, ±1/ 3, ±1/ 3 by full calculation: use standard identity, substitute, simplify step by step to reach ± 1/ 3, ±1/ 3, ±1/ 3.
Ref: NCERT Mathematics Class XII — Vectors and 3D Geometry
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