The binding energy of the deuterium is 2.23 MeV. The mass defect in amu is
Mass defect Δm=E/931.5=2.23/931.5≈0.00239 amu.
Ref: NCERT Physics Class 12 Chapter 13 Nuclei
#deuterium
1 public question tagged with this topic.
1 public question tagged with this topic.
Mass defect Δm=E/931.5=2.23/931.5≈0.00239 amu.
Ref: NCERT Physics Class 12 Chapter 13 Nuclei
Add the app to your home screen for faster access.