We use cookies to improve your experience and understand how Examtube is used. You can accept analytics cookies or continue with essential cookies only.
Privacy policy3 public questions tagged with this topic.
Soda lime (NaOH + CaO) is commonly used to remove the carboxyl group from carboxylic acids, forming hydrocarbons. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.
Pentanoic acid (CH₃CH₂CH₂CH₂COOH) forms calcium pentanoate, which decarboxylates to heptan-4-one (CH₃CH₂CH₂COCH₂CH₂CH₃), an eight-carbon ketone.
Ref: NCERT Class 12 Chemistry > Chapter 12: Aldehydes, Ketones and Carboxylic Acids > Topic: Reactions due to α-Hydrogen - Aldol, Cannizzaro and Acidity of Carboxylic Acids
Step 1: LiAlH₄ reduces hexanoic acid (CH₃(CH₂)₄COOH) to hexan-1-ol (CH₃(CH₂)₅OH). Step 2: Clemmensen-like reduction (not direct) or dehydration followed by hydrogenation could work, but Wolff-Kishner on the derived ketone fits PDF scope.
Ref: NCERT Class 12 Chemistry > Chapter 12: Aldehydes, Ketones and Carboxylic Acids > Topic: Physical Properties and Nucleophilic Addition Reactions
This page is supported by advertisements. An ad blocker is stopping those ads from loading, so we cannot show the rest of the page yet. Pause the blocker for this site, then continue. We will check again automatically.
You can keep using this site after advertisements are allowed to load.
