A \( 5 \, \Omega \) resistor carries a current of \( 2 \, \text{A} \) for \( 10 \, \text{s} \). How much energy is dissi
**Mobility** μ = v_d/E = e τ/m, τ relaxation time (s), measures ease of electron drift under field E (V/m). Conductivity σ = n e μ = 1/ρ, linking microscopic τ to macroscopic resistivity, explaining why metals conduct well due to large n and τ. Energy dissipated: W = I² R t . Given: I = 2 A , R = 5 Ω , t = 10 s . Substitute: W = (2)² × 5 × 10 = 4 × 50 = 200 J . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V
Ref: NCERT > Physics Book > Current Electricity > Electric Current, Drift Velocity and Mobility