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#coil orientation

2 public questions tagged with this topic.

In an AC generator, the maximum emf occurs when the coil is in which orientation relative to the magnetic field?

**Rotational emf** when coil area A rotates with angular speed ω in uniform field B, flux Φ = B A cos ωt, emf e = -N dΦ/dt = N B A ω sin ωt, maximum e₀ = N B A ω, frequency = ω/2π. For square side 22 cm area 0.0484 m² N=1 ω=14 rad/s B=0.15 T, e₀=1×0.15×0.0484×14=0.1016 V, sinusoidal. The maximum emf occurs when the rate of flux change is greatest, which happens when the coil is perpendicular to the field ( sinθ = 1 ). Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v

Ref: NCERT > Physics Book > Electromagnetic Induction > Rotational EMF and AC Generator

A coil is placed in a uniform magnetic field of 0.5 T. The area of the coil is 0.04 m², and the angle between the field

**Magnetic flux** Φ = B·A = B A cosθ, B magnetic field (T), A area (m²), θ angle between B and normal to area, unit Wb = T·m², Faraday's law induced emf e = -N dΦ/dt, N turns, negative sign Lenz's law indicating opposition, magnitude |e| = N |ΔΦ/Δt|, for 100 turns ΔΦ=0.03 Wb Δt=0.06 s e=100×0.03/0.06=50 V. Initial flux: Φ_i = B A cos 0° = 0.5 × 0.04 × 1 = 0.02 Wb . Final flux: Φ_f = B A cos 90° = 0.5 × 0.04 × 0 = 0 Wb . Δ Φ = 0.02 - 0 = 0.02 Wb , Δ

Ref: NCERT > Physics Book > Electromagnetic Induction > Magnetic Flux and Faraday's Laws of Induction