In the Carius method, 0.22 g of a compound gave 0.431 g of AgCl. What is the percentage of chlorine?
Mass of Cl = (35.5/143.5) × 0.431 = 0.1066 g. Percentage = (0.1066/0.22) × 100 = 48.45% ≈ 48%.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation
