101 public questions tagged with this topic.
Chromic acid (H â‚‚ CrO â‚„ ) oxidizes primary alcohols to aldehydes and secondary alcohols to ketones, producing a color change. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Reactivity decreases with steric hindrance and conjugation: CH₃COCH₂CH₃ (ketone) < C₆H₅CHO (aromatic aldehyde) < CH₃CH₂CHO (aliphatic aldehyde).
Ref: NCERT Class 12 Chemistry > Chapter 12: Aldehydes, Ketones and Carboxylic Acids > Topic: Reactions due to α-Hydrogen - Aldol, Cannizzaro and Acidity of Carboxylic Acids
Pentanal (CH₃CH₂CH₂CH₂CHO), a straight-chain aldehyde, has stronger dipole-dipole interactions than branched isomers like 2-methylbutanal, giving it the highest boiling point.
Ref: NCERT Class 12 Chemistry > Chapter 12: Aldehydes, Ketones and Carboxylic Acids > Topic: Reactions due to α-Hydrogen - Aldol, Cannizzaro and Acidity of Carboxylic Acids
Boiling points depend on intermolecular forces: CH₃COOH (strong H-bonding) > CH₃CH₂OH (H-bonding) > CH₃CHO (dipole-dipole).
Ref: NCERT Class 12 Chemistry > Chapter 12: Aldehydes, Ketones and Carboxylic Acids > Topic: Reactions due to α-Hydrogen - Aldol, Cannizzaro and Acidity of Carboxylic Acids
Boiling points: Pentanoic acid (strong H-bonding) > Hexan-1-ol (H-bonding) > Hexanal (dipole-dipole).
Ref: NCERT Class 12 Chemistry > Chapter 12: Aldehydes, Ketones and Carboxylic Acids > Topic: Reactions due to α-Hydrogen - Aldol, Cannizzaro and Acidity of Carboxylic Acids
Boiling points: Pentanoic acid (strong H-bonding) > 2-Methylbutan-1-ol (H-bonding) > Pentanal (dipole-dipole).
Ref: NCERT Class 12 Chemistry > Chapter 12: Aldehydes, Ketones and Carboxylic Acids > Topic: Chemical Reactions - Reduction, Oxidation and Tests - Tollens, Fehling, Iodoform
The compound has a 5-carbon chain with a carboxylic acid group (pentanoic acid) and a double bond between C-3 and C-4: pent-3-enoic acid.
Ref: NCERT Class 12 Chemistry > Chapter 12: Aldehydes, Ketones and Carboxylic Acids > Topic: Chemical Reactions - Reduction, Oxidation and Tests - Tollens, Fehling, Iodoform
The compound has a 4-carbon chain with a carboxylic acid group (butanoic acid) and a double bond between C-2 and C-3: but-2-enoic acid.
Ref: NCERT Class 12 Chemistry > Chapter 12: Aldehydes, Ketones and Carboxylic Acids > Topic: Chemical Reactions - Reduction, Oxidation and Tests - Tollens, Fehling, Iodoform
[Cr(en)2(H₂O)2]3+ is octahedral with 2 en (bidentate) and 2 H₂O (unidentate). The 2 en ligands create the propeller-like structure causing chirality.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Isomerism - Optical Isomerism and Linkage Ionisation Solvate
Linkage isomerism occurs with ambidentate ligands like NO₂−, which can bind via N or O. [Co(NH₃)5NO₂]2+ can form [Co(NH₃)5ONO]2+, showing linkage isomerism.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Isomerism - Optical Isomerism and Linkage Ionisation Solvate
[Co(en)2(H₂O)Cl]2+ (octahedral) with 2 bidentate en, 1 H₂O, and 1 Cl− forms a chiral complex without symmetry.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Isomerism - Optical Isomerism and Linkage Ionisation Solvate
Transition metals and their compounds are used as catalysts, pigments, and in alloy formation. While platinum is used as an inert electrode in many electrochemical setups, the option 'inert electrodes' may be considered not primary/general for most transition metals.
Ref: NCERT Class 12 Chemistry > Chapter 4: d and f Block Elements > Topic: Applications of d and f Block Elements
