A capillary tube of radius 0.65 mm is dipped in water ( S = 0.0727 N/m, rho = 1000 kg/m³, cos θ = 1 ). What is the cap
Given: A capillary tube of radius 0.65 mm is dipped in water ( S = 0.0727 N/m, rho = 1000 kg/m³, cos θ = 1 ). What is the capillary rise? (Take g = 9.8 m/s² ) These values define the system as per NCERT data. Formula: h = 2 S cos θ/rho g a. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: S = 0.0727 N/m, rho = 1000 kg/m³, g = 9.8 m/s², a = 0.65 × 10â»Â³ m . h = frac2 × 0.0727 × 11000 × 9.8 × 0.65 × 10â»Â³= 0.02285 m = 2.285 cm . Result: The computed value matches the expected outcome and confirms the correct choice. Units and pow
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.
