In a series LCR circuit the voltage across the resistance, capacitance and inductor is 10 V each. If the capacitor is sh
V_R=10V, V_L=V_C=10V resonance, if C shorted V_L still 10V? Actually V=√(VR^2+(VL-VC)^2).
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
