6 public questions tagged with this topic.
We can see that solving fully: apply relevant formula, put numbers, compute. Result comes as 0. Easy verification shows it satisfies condition.
Ref: NCERT Mathematics Class XII — Probability
We can see that binomial n=6, p=0.5. P=6C2(1/2)^6=15/64. Calculation: 6C2=15, (1/2)^6=1/64.
Ref: NCERT Mathematics Class XII — Probability
Recall the rule success getting 4: p=1/6, n=72, q=5/6. Variance=npq=72×1/6×5/6=10. Complete formula.
Ref: NCERT Mathematics Class XII — Probability
In easy words, 3·5C2 p²q³=5C3 p³q², so 30q=10p, 3(1-p)=p, 3-3p=p, p=3/4. Complete solving.
Ref: NCERT Mathematics Class XII — Probability
Think of it like this: p=0.5, n=5. P(at most 1 negative)=P0+P1= C5,0(0.5)^5+C5,1(0.5)^5=1/32+5/32=6/32=3/16. Full.
Ref: NCERT Mathematics Class XII — Probability
We know that mean np=4 and p=0.4 gives n=10. Variance=npq=4×0.6=2.4. Complete using q=1-p.
Ref: NCERT Mathematics Class XII — Probability
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