The limiting molar conductivity of BaCl₂ is 280 S cm² mol⁻¹. If λ°Ba²⁺ = 127 S cm² mol⁻¹ , what is λ°Cl⁻ ?
Lambdam° = λ°Ba²⁺ + 2λ°Cl⁻ . 280 = 127 + 2λ°Cl⁻ , 2λ°Cl⁻ = 153 , λ°Cl⁻ = 76.5 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law