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#angular acceleration

19 public questions tagged with this topic.

PHYSICS

The dimensional formula of angular acceleration is [T^{-2] . Which quantity shares the same dimensions?

Given: The dimensional formula of angular acceleration is [T^{-2] . Which quantity shares the same dimensions? These values define the system as per NCERT data. Formula: (a) [v² / r²] = [L T^{-1]² / [L]² = [T^{-2]. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: (b) [a / r] = [L T^{-2] / [L] = [T^{-2] . (c) [F / m r] = [M L T^{-2] / [M L] = [T^{-2] . (d) [v t / r] = [L T^{-1] [T] / [L] = [T⁰] . (b) matches (simplest match chosen). Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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Vector Product and Rotational Kinematics

What is the primary source of angular acceleration in a rigid body?

Angular acceleration (α) is caused by net external torque (τ = Iα), which drives rotational change. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Net external torque. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Vector Product and Rotational Kinematics

A wheel with moment of inertia 6kg m2 rotates at 3rad/s. A torque of 12Nm acts for 3s. What is its final angular velocit

α = τI = 126 = 2rad/s2. Δω = αt = 2×3 = 6rad/s. ω = ω0+Δω = 3+6 = 9rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 9 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Rotational Motion Applications

What is the condition for a rigid body to have zero angular acceleration?

Angular acceleration is zero when the net torque is zero (τ = Iα), as torque drives rotational change. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Net torque is zero. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Rotational Motion Applications

A wheel of radius 0.4m and moment of inertia 1.6kg m2 is accelerated by a torque of 8Nm. What is its angular acceleratio

Torque: τ = Iα. τ = 8Nm, I = 1.6kg m2. α = τI = 81.6 = 5rad/s2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5 rad/s². This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Conservation of Angular Momentum

What is the effect of a force applied at the axis of rotation on a rigid body?

A force applied at the axis (r = 0) produces no torque (τ = rFsin⁡θ = 0), so it cannot cause rotation about that axis. As per NCERT, applying relevant law/formula with correct units and sign convention leads to It causes no rotation. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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