What is the product when CH₃CH₂CH₂I reacts with excess NH₃ ?
Excess NH₃ substitutes I in CH₃CH₂CH₂I to form CH₃CH₂CH₂NH₂ (propylamine) via SN₂ .
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Physical Properties - Boiling Point Dipole Moment Solubility
