When ethyl amine is treated with methyl magnesium bromide, the product is:
Methane correct as per chemistry principle.
Ref: NCERT Chemistry Class XI and XII
13 public questions tagged with this topic.
Methane correct as per chemistry principle.
Ref: NCERT Chemistry Class XI and XII
Aniline (C₆H₅NH₂) reacts with excess Br₂ in water to form 2,4,6-tribromoaniline, a white precipitate, as per the PDF’s chemical properties.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Chemical Reactions - Alkylation, Acylation and Electrophilic Substitution
None of the listed amines form a compound with two nitrogens with CH₃COCl; however, if misinterpreted, CH₃NH₂ forms CH₃NHCOCH₃ (one N). Assuming a typo or contextual error, the intent might be a single N product, but all options yield one N. Correcting intent: primary amines like CH₃NH₂ react typically. Here, CH₃NH₂ is chosen for standard reaction.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Chemical Reactions - Alkylation, Acylation and Electrophilic Substitution
Tertiary amines like (CH₃CH₂)₃N do not form nitrosamines with HNO₂, unlike secondary amines, as per the PDF’s chemical properties.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Preparation - Hoffmann Bromamide and Reduction of Nitro Compounds
Ethylamine (CH₃CH₂NH₂) reacts with HNO₂ to produce ethanol (CH₃CH₂OH) and nitrogen gas, as per the PDF’s chemical properties.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Preparation - Hoffmann Bromamide and Reduction of Nitro Compounds
Primary aliphatic amines like CH₃CH₂CH₂NH₂ react with HNO₂ to form alcohols (e.g., propan-1-ol) and N₂, as described in the PDF’s chemical properties.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Preparation - Hoffmann Bromamide and Reduction of Nitro Compounds
Aniline (C₆H₅NH₂) forms 2,4,6-tribromoaniline with Br₂ water (precipitate) but does not liberate N₂ with HNO₂ like aliphatic primary amines, as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Preparation - Hoffmann Bromamide and Reduction of Nitro Compounds
Secondary amines like (CH₃)₂NH form nitrosamines (yellow oily liquids) with HNO₂, as per the PDF’s chemical reactions.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Preparation - Hoffmann Bromamide and Reduction of Nitro Compounds
Methylamine (CH₃NH₂) reacts with HNO₂ to form methanol (CH₃OH), the smallest alcohol, as per the PDF’s chemical properties.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Preparation - Hoffmann Bromamide and Reduction of Nitro Compounds
Propan-1-amine (CH₃CH₂CH₂NH₂) forms propyl isocyanide (CH₃CH₂CH₂NC) in the carbylamine reaction, as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Primary aliphatic amines like CH₃CH₂NH₂ form isocyanides (foul odor) in the carbylamine reaction, as per the PDF’s chemical properties.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Methylamine (CH₃NH₂) forms methyl isocyanide (CH₃NC) in the carbylamine reaction, as per the PDF’s chemical properties.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
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