4 public questions tagged with this topic.
For 1-butene ( CH₃CH₂CH=CH₂ ), HI adds via Markovnikov's rule, forming CH₃CH₂CHICH₃ (2-iodobutane).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
CH₃CH=CHCH₃ (2-butene) with HCl forms CH₃CHClCH₂CH₃ , which eliminates HCl with alcoholic KOH to form 1-butene ( CH₃CH₂CH=CH₂ ).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
For 1-butene ( CH₂=CHCH₂CH₃ ), HBr adds via Markovnikov's rule, forming CH₃CHBrCH₂CH₃ (2-bromobutane).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Classification and Nomenclature and Isomerism of Haloalkanes
For 2-pentene ( CH₃CH=CHCH₂CH₂CH₃ ), HBr adds via Markovnikov's rule, forming CH₃CHBrCH₂CH₂CH₃ (2-bromopentane).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Classification and Nomenclature and Isomerism of Haloalkanes
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