The solubility of Ag₂CrO₄ is 1.3 × 10⁻⁴ M . What is its Ksp ?
For Ag₂CrO₄ 2Ag+ + CrO₄²⁻ , [Ag+] = 2S = 2.6 × 10⁻⁴ , [CrO₄²⁻] = S = 1.3 × 10⁻⁴ . Ksp = (2.6 × 10⁻⁴)² (1.3 × 10⁻⁴) = 8.79 × 10⁻¹² .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
