9 public questions tagged with this topic.
Aniline ( C₆H₅NH₂ ) reacts with acetyl chloride ( CH₃COCl ) to form acetanilide ( C₆H₅NHCOCH₃ ), an acylation product, with the base neutralizing HCl .
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Ethylamine (CH₃CH₂NH₂) reacts with butanoyl chloride (CH₃CH₂CH₂COCl) to form N-ethylbutanamide (CH₃CH₂CH₂CONHCH₂CH₃), as per the PDF’s acylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Aniline (C₆H₅NH₂) reacts with one mole of acetyl chloride to form acetanilide (C₆H₅NHCOCH₃), as per the PDF’s acetylation reaction.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Aniline (C₆H₅NH₂) reacts with propanoyl chloride (CH₃CH₂COCl) to form N-phenylpropanamide (C₆H₅NHCOCH₂CH₃), as per the PDF’s acylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Ethylamine (CH₃CH₂NH₂) reacts with acetyl chloride (CH₃COCl) to form N-ethylacetamide (CH₃CONHCH₂CH₃), as per the PDF’s acetylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Aniline (C₆H₅NH₂) reacts with acetic anhydride ((CH₃CO)₂O) to form acetanilide (C₆H₅NHCOCH₃), as per the PDF’s acetylation reaction.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Aniline (C₆H₅NH₂) reacts with acetyl chloride (CH₃COCl) to form acetanilide (C₆H₅NHCOCH₃), as per the PDF’s acetylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Aniline reacts with acetyl chloride to form acetanilide (C₆H₅NHCOCH₃) via acetylation, releasing HCl.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Ethylamine (CH₃CH₂NH₂) reacts with propanoyl chloride (CH₃CH₂COCl) to form N-ethylpropanamide (CH₃CH₂CONHCH₂CH₃), as per the PDF’s acylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
