A rectangular loop of area \( 0.07 \, \text{m}^2 \) with 12 turns carries \( 3.5 \, \text{A} \) in a field of \( 0.5 \,
**Magnetic field due to long straight wire** at distance r is B = μ₀ I/(2π r), μ₀ = 4π×10⁻⁷ T·m/A, direction circular around wire given by right-hand grip rule. For I = 18 A, r = 0.15 m, B = 2×10⁻⁷×18/0.15 = 2.4×10⁻⁵ T, illustrating 1/r dependence. tau = N I A B sin θ , where θ = 60° to plane means sin 30° with normal. tau = 12 × 3.5 × 0.07 × 0.5 × sin 60° = 1.47 × 0.866 = 1.273 ≈ 1.27 N m . Using F = q v B sinθ, F = I l B sinθ, B =
Ref: NCERT > Physics Book > Moving Charge and Magnetism > Magnetic Field Due to Current - Straight Wire and Circular Loop