Practice question
Question
For Ca(OH)2(s) <=> Ca²+ + 2OH-, K_{sp = 5.5 × 10â»â¶. What is [Ca²+] in 0.01 M NaOH ?
Explanation
Given:
For Ca(OH)2(s) <=> Ca²+ + 2OH-, K_{sp = 5.5 × 10â»â¶. What is [Ca²+] in 0.01 M NaOH ?
These values define the system as per NCERT data.
Formula:
K_{sp = [Ca²+][OH-]², [OH-] = 0.01 + 2S approx 0.01.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
5.5 × 10â»â¶= [Ca²+] · (0.01)², [Ca²+] = 5.5 × 10â»Â² M.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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