Practice question

Given: A wire of length 2.2 m carrying 3.5 A is at 60° to a magnetic field of 0.2 T . What is the force on the wire? Formula: Force F = I l B sin θ. Substitution & Calculation: F = 3.5 × 2.2 × 0.2 × sin 60° = 7.7 × 0.2 × 0.866 = 1.3336 approx 1.33 N . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.