Practice question

Given: A uniform rod of mass 5 kg and length 2 m is pivoted at its nter. What is its moment of inertia about the pivot? Formula: For a rod pivoted at its nter: I = 1/12 M L². Substitution & Calculation: M = 5 kg, L = 2 m . I = 1/12 × 5 × (2)² = 20/12 = 5/3 approx 1.67 kg m² . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.