Practice question

Given: A square loop of side 0.18 m with 30 turns carries 2 A in a magnetic field of 0.4 T . The plane of the loop is at 60° to the field. What is the torque? Formula: Torque tau = N I A B sin θ, where A = 0.18 × 0.18 = 0.0324 m². Substitution & Calculation: tau = 30 × 2 × 0.0324 × 0.4 × sin 60° = 0.7776 × 0.866 = 0.6734 approx 0.67 N m . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.