Practice question
Question
A coil of self-inductance 1.2 H has its current increased from 2 A to 6 A in 0.4 s. What is the magnitude of the induced emf?
Explanation
Given:
A coil of self-inductance 1.2 H has its current increased from 2 A to 6 A in 0.4 s. What is the magnitude of the induced emf?
Formula:
ε = L Δ I/Δ t.
Substitution & Calculation:
Δ I = 6 - 2 = 4 A, Δ t = 0.4 s . ε = 1.2 × 4/0.4 = 1.2 × 10 = 12 V .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Related blogs
Guides and insights connected to this topic
Electricity Notes - Electric Current, Potential, Ohm's Law, Resistance, Heating Effect and Power
Learn the basics of electric current, circuits, potential, Ohm's law, resistance, heating effect and power in clear, concise notes.
Light Reflection and Refraction Notes - Spherical Mirrors, Lenses, Power of Lens and Numericals
Explore key optics concepts: laws of reflection, spherical mirrors, lens power and practice numericals in a concise note.
Enzyme Technology
Enzyme The enzyme is a substance that acts as a catalyst in living organisms, regulating the rate at which chemical reactions proc...
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.